Diapositive PPT
pH de précipitation de Zn(OH)2
Zn(OH)2 = Zn2+ + 2 OH- : pKs = 17,15
2 log[OH-] = log Ks - log [Zn2+]
-2 pOH =- pKs - log [Zn2+]
pOH = 1/2 ( pKs + log [Zn2+] )
pH = 14 - 1/2 ( pKs + log [Zn2+] )
pH = 14 - 1/2 ( pKs + log C0 )
pH = 14 - 1/2 ( 17,15 - 3 )
Diagramme de prédominance